CS180 Homework 2

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1. You are given n songs {1, 2, . . . , n} and 2 preference lists A = {a1
, a2
, . . . , an
} and B = {b1
, b2
, . . . , bn
}. Each ai
is a
positive integer and ai = k means the song k is ranked at i
th position in list A. An inversion between A and B is a pair
(i, j) such that song i is ranked before song j in list A, but song j is ranked before song i in list B. In the lecture, we
showed that to count the number of inversions, we can permute the songs in both lists according to the index of list
A. More specifically, the permutation is defined by ai
7→ i for all i. We claimed that the number of inversions after
applying the permutation does not change. Actually, this claim works for any permutation. Prove that the number
of inversions does not change if we apply an arbitrary permutation.
2. Suppose you are given two sets of n points in the plane, one set {p1
, p2
, …, pn
} on the line y = 0 and the other set
{q1
, q2
, …, qn
} on the line y = 1. Create a set of n line segments by connecting each point pi
to the corresponding
point qi
. The number of intersections is the number of how many pairs of these line segments are crossing.
An example with 11 intersections
(a) Consider the two sets of n points are two preference lists of n songs. The value of pi and qi
represents how song
i is ranked in two preference lists. Prove that the number of inversions in two preference lists is equivalent to
the number of intersections.
(b) Describe an algorithm to calculate the number of intersections in O(n log n) time.
3. A celebrity among n persons is someone who is known by everyone but does not know anyone. Give an iterative
algorithm to find the celebrity among n people.
4. The diameter of a tree is the number of edges in the longest path in the tree.
(a) Given a rooted directed tree, find the diameter of the underlying undirected tree using a recursion, computes
the result of the original problem given that we removed the root and solved the problem for the remaining
rooted trees.
(b) Write the iterative version of this algorithm, and analyze its complexity, which should be linear in n, the number
of nodes in the tree.
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